4. Find the complex number, n Cartesian form, such that it satisfies the equation (3- V3)(V3...
4. (15 points) Find all the complex solutions of the equation +(V3-3i)(1+2)40. Express the results in Cartesian form (you may express your answer as a function of k, eg. z = eik cos (kπ/2) + isin(kn/2), k = 0, 1, 2, 3, without explicitly evaluating the expression for each k). 2-
4. (15 points) Find all the complex solutions of the equation +(V3-3i)(1+2)40. Express the results in Cartesian form (you may express your answer as a function of k, eg....
3. Simplify the complex number 2+54 + vZe(7) into Cartesian form. 1+3i
3. Express each of the following in simplified Cartesian form. a) (v2- V60)0 (V2 + V65)25 (b) 21010(-1 +)0(+) 4. Find the complex number z, in Cartesian form, such that it satisfies the equation 5. Find all solutions of the equation r 160 Express any complex solutions in Cartesian form, simplified as much as possible.
Use the polar form of the complex number 5 i to find a value in Cartesian form, z = x+iy. Enter the exact answer. Z= 0+iv 5 Edit
#1,5,9 and #13,17,21,25 please.
In Exercises 1-12, graph each complex number in the complex plane 3. -2 4i 2 2. 3 5i 7.-3i 8.-5i 6. 7 47 19 7 15 2 11 2 12. 10 10 each complex number in polar form 15. 1 V3i 14. 2 + 2i 16. -3- V3i 3. 1-i 20. -V3+i 18. V5_V5İ 19. V3-3i 17-44i 24. -8-8V3i 22. 2 + Oi 2 23, 2v3-2i 21. 3 +0i V3 1 1 V3 28·16+161 26, 1...
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(1 point) Eliminate the parametert to find a Cartesian equation for I=+2 y= 10 + 2t 2 = Ay? + By+C where A= and B = and C = (1 point) Consider the parametric curve: 2 = 8 sin 0, y = 8 cos 0, 0<<A The curve is (part of) a circle and the cartesian equation has the form 2? + y2 = R2 with R= The initial point has coordinates: 3 = !!! ,y=...
5. Consider the complex number z 3i Find the polar form Find z4. Put in non-polar form a. b.
5. Consider the complex number z 3i Find the polar form Find z4. Put in non-polar form a. b.
Find the solution of the differential equation that satisfies the given initial condition. * In x = y(1+ V3 + y2)y, y(1) = 1 x?n(x) - ***+ ** – 3y2 + }(3+x2)(+) *
Eliminate the parameter t to find a Cartesian equation in the form 3 = f(y) for: Sz(t) - 4t² ly(t) = – 9+ 4t The resulting equation can be written as 2 =
Problem 1.4 (a) Let 2 = 3e32"/3. Convert z to Cartesian form. (b) Let z = 6 - 23. Convert z to polar form. (c) Let 2 = 1-. Calculate 25. (d) Let z be a complex number and 23 = V3+j. Find all possible values of 2.