Question

The A-36 steel drill shaft of an oil well extends 12000 ft into the ground. The pipe used to drill the well is suspended freely from the derrick at A. (Figure 1) The shaft consists of three different sizes of pipe, AAB = 2.10 in.2, ABC = 1.50 in?, and ACD = 1.00 in., each having the length and weight per unit length indicated. Figure < 1 of 1 > AAB 5000 ft WAB= 3.2 lb/ft Авс 5000 ft Wec= 2.8 lb/ft Аср wcd= 2.0 lb/ft 2000 ft

Answer 1

solution : Finding the stres at "c" we know that the Internal Resisting force offered by a body by applying an Enternal force is known as stren. Mathematically on lead a o telo Pe = 2#)(2000 ) = 4000 lb Asl in Oci 4000-4000 psº Joca 4000 psil Pg=(2-8)(5000) = 14000 lbs A = 1.5 JOB:93 33• 333 psi 6 = 14000 on = Pas+ Pietre PA+ Potpc. OA A PA: (3.2)(5000) = 16000 Aarloin SAE 16000 + 14000 + 4000 TE: 16190.476 P8:] 2.1

P(w): 2.84 +H000 fca)= 21. I 2.80. A pin) = 302x + 18000 Tu, 3.21. 2,spee) NIM 2 X 212000) 4000 Finding Deflection at " So: el plan de where te fainos Modulour. So: 3 ) Aus Ei I Aru) E 5000 5000 2000 anda +/(2.84 +4000) du (3124 +18000) dm (2.1) (29) (106) Jó 11.5) (29) (109) ó - 2000 5000. +1 8000M +1% 2.85 2 + 400On poo 2 i 106 2. lo So detery (2) got + (-a)/(5otokowe) 14(57say (50oof 2.1 So bacio 4X106 + 36166666x0° + 61.9047619 x106] So = 102.5714286 X 106 (29) (106) So = 365 369 Ft