A bat, flying at 20.0 m/s, emits a chirp at 40.0 kHz. If this sound pulse is reflected by a wall, what is the frequency of the echo received by the bat? (V sound = 340 m/s. unit in kHz)
Here both source and observer is bat itself,
Using the doppler effect of sound formula,
f'=frequency of echo
f=original frequency
Vsound=Velocity of sound
Vbat=Velocity of bat
f'= [(Vsound+Vbat)/(Vsound-Vbat)] f
f'=[(340+20)/(340-20)]*(40khz)
f'=45khz
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