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For a Friedel-Crafts alkylation reaction between 1,4-dimethoxybenzene with 3-methyl-2-butanol and sulfuric acid what product was formed...

For a Friedel-Crafts alkylation reaction between 1,4-dimethoxybenzene with 3-methyl-2-butanol and sulfuric acid what product was formed in this reaction? Use a discussion of the reaction mechanism, IR, and NMR data to justify your conclusion. A figure should be included to aid in the discussion of the reaction mechanism.

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Answer #1

In the IR spectrum for C=C bond stretching one band will come at around 1680-1575 cm-1.

In the IR spectrum for C-H bond stretching band will come at around 3100-3000 cm-1 for phenyl group.

In the IR spectrum for C-H bond stretching band will dispaly at around 2985-2865 cm-1 for CH and CH3 group.

In the IR spectrum for C-O bond stretching one band will come at around 1445-1300 cm-1.

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For a Friedel-Crafts alkylation reaction between 1,4-dimethoxybenzene with 3-methyl-2-butanol and sulfuric acid what product was formed...
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