When 3-bromo-2,2-dimethylbutane is treated with potassium tert-butoxide, a single product, A, having the formula C6H12 is formed. When 3,3-dimethyl-2-butanol is treated with sulfuric acid, the major product, B, has the formula C6H12. Given the following NMR data, what are the structures of A and B?Write reactions for the formation of A and B and draw a splitting diagram for the protons at 4.82, 4.93, and 5.83 ppm in compound A
1H NMR of A: 1.01 (s, 9H), 4.82 (dd, 1H, J = 10, 1.7 Hz), 4.93 (dd, 1H, J = 18, 1.7 Hz), 5.83 (dd, 1H, J = 18, 10 Hz).
1H NMR of B: 1.60 (s, 12H).
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When 3-bromo-2,2-dimethylbutane is treated with potassium tert-butoxide, a single product, A, having the formula C6H12 is formed. When 3,3-dimethyl-2-butanol is treated with sulfuric acid, the major product, B, has the formula C6H12. Given the following N
When 2-bromo-3,3-dimethylbutane is treated with K+ −OC(CH3)3, a single product T having molecular formula C6H12 is formed. When 3,3-dimethyl-2-butanol is treated with H2 SO4, the major product U has the same molecular formula. Given the following 1H NMR data, what are the structures of T and U? Explain in detail the splitting patterns observed for the three split signals in T.1H NMR of T: 1.01 (singlet, 9 H), 4.82 (doublet of doublets, 1 H, J = 10, 1.7 Hz), 4.93...