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An independent random sample is selected from an approximately normal population with an unknown standard deviation. a) Given
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Answer #1

a) Standard Error , SE = s/√n =   8.5/√32=   1.5026

b)

Level of Significance ,    α =    0.05          
degree of freedom=   DF=n-1=   31          
't value='   tα/2=   2.040   [Excel formula =t.inv(α/2,df) ]      
                  
Standard Error , SE = s/√n =   8.5/√32=   1.5026          
margin of error , E=t*SE =   2.0400   *   1.5026   =   3.0653
                  
confidence interval is                   
Interval Lower Limit = x̅ - E =    24.30   -   3.0653   =   21.234692
Interval Upper Limit = x̅ + E =    24.30   -   3.0653   =   27.365308
95%   confidence interval is (   21.23   < µ <   27.37   )

c) answer: 24,27

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