Question

3.

(15

points) Fill in the method template below to make a working method. Make sure

your method conforms to the instructions given in the comments for the method.

public

static

boolean

allIn

(

Set

<

Integer

>

set

,

List

<

Integer>

list

)

{

// This method takes

a

set and a list as inputs and returns true if every

// element in the list is also an element of the set. Otherwise

// it returns false. If the list is empty then it should return false

.

//

YOU SHOULD NOT IMPLEMENT THIS METHOD RECURSIVELY!

3.

(15

points) Fill in the method template below to make a working method. Make sure

your method conforms to the instructions given in the comments for the method.

public

static

boolean

allIn

(

Set

<

Integer

>

set

,

List

<

Integer>

list

)

{

// This method takes

a

set and a list as inputs and returns true if every

// element in the list is also an element of the set. Otherwise

// it returns false. If the list is empty then it should return false

.

//

YOU SHOULD NOT IMPLEMENT THIS METHOD RECURSIVELY!

Answer 1

The java code for allIn() function definition is given here:

public static boolean allIn (Set<Integer> set,List<Integer> list)
{

if(set.isEmpty()||list.isEmpty())//checking list or set are empty or not
{
return false;
}
  
List<Integer> list1 = new ArrayList<Integer>(set);//converting set into list

if(list1.equals(list))
{
return true;
}
else
{
return false;
}
  
}

Complete working code for this problem is given here:

 import java.util.*; public class EqualTest { public static void main(String[] args) { //Creating a list List<Integer> list = new ArrayList<Integer>(); list.add(0, 1); // adds 1 at 0 index list.add(1, 2); // adds 2 at 1 index //Creating a Set Set<Integer> set = new HashSet<Integer>(); set.add(1); //adds 1 at 0 index set.add(2); //adds 2 at 1 index //calling allIn() function boolean Result=allIn(set,list); System.out.println(Result); } public static boolean allIn (Set<Integer> set,List<Integer> list) { if(set.isEmpty()||list.isEmpty())//checking list or set are empty or not { return false; } List<Integer> list1 = new ArrayList<Integer>(set);//converting set into list if(list1.equals(list)) { return true; } else { return false; } } } 

OUTPUT for this problem is :

True

//Because the given set and list are equal

If list contains [1,3] and set contains {2,3} the output will be false