process | Arrival Time | Burst Time |
P1 | 0 | 10 |
P2 | 2 | 7 |
P3 | 4 | 4 |
P4 | 5 | 2 |
P5 | 6 | 1 |
I need the solution on
non-preemptive SJF & Preemptive SJF
the Gantt Chart , Wating time and Average Wating time
becouse I am really confused :(
Q.2] Answer the following questions Process Burst Time Priority P1 3 1 P2 8 3 P3 2 4 P4 4 5 P5 5 1 (21 points) Consider the set of processes shown in the table above, with the length of the CPU-burst time given in milliseconds. The processes are assumed to have arrived in the order P5, P4, P3, P2 , and P1, all approximately at time 0. Draw three Gantt charts illustrating the execution of these processes using SJF,...
Consider 5 processes whose Arrival time and CPU Burst time is as follows (Process no: Arrival time: Burst time): P1:0,6 P2:2,4 P3:3,2 P4: 5,5 P5: 6,9 Assume that the processes are scheduled using SJF (Non-preemptive) scheduling algorithm. The average waiting and turaround time is O 5.45, 11.60 O 5.40, 10.60 O 6.50, 10.99 O 5.45, 11.60
Burst Time Arrival Time P1 54 2 P2 12 3 P3 26 4 P4 16 5 P5 8 6 P6 92 7 use SRTF (1) Gant chart (2) Waiting time and Turn around time for every process (3) Average WT and Average TAT
8. Consider the following 5 processes in the ready queue: Process Burst Priority Arrival time n w P1 P2 w N P3 P P - W WE O P4 N P5 N A O Draw Gantt charts illustrating the execution of these processes for each of the following algorithms: (a) preemptive SJF, (b) RR (with quantum = 1), (C) FCFS, and (d) preemptive priority, and calculate the respective turnaround and waiting times.
OS CPU Scheduling
1. Given the following processes Process Arrival Time 0 Priority 5 P1 P2 P3 P4 Burst Time 10 5 8 15 2 2 3 2 a) Please demonstrate the SJF and LJF algorithms on the above. (Note: if they mention SJF or any other, make sure u do both the non- preemptive and preemptive) b) What are the differences between them?
Process Arrival Time CPU Burst Time P1 0 7 P2 3 8 P3 4 3 P4 6 7 For the following algorithms, calculate the average wait time and turn around time. Round-robin with quantum of one time-unit
Consider the following set of processes, with the length of CPU burst in milliseconds. Process PI P2 P3 P4 P5 Arrival time 00 02 03 06 30 Burst time 10 12 14 16 05 Draw a Gantt chart that illustrates the execution of these processes using the preemptive shorte st job first (SJF) algorithm. Hence find the average waiting time. Draw a Gantt chart that illustrate the execution of these processes using preemptive priority scheduling algorithm. Given priority of each...
V. Round Robin and SJF comparison 6 Process Arrival Time CPU Burst Time P1 0 9 P2 4 4 P3 6 P4 For each of the following algorithms, draw a Gantt chart and calculate the average wait time and turn around time. 1. Round robin with quantum=1 time unit 2. Round-robin with quantum=3 time-units 3. SJF WI preemption (Shortest Remaining Time First), assume quantum=3 4. SJE Wlo preemption 5. ECES
4. Consider a ready queue with four processes :- Process Arrival Time Burst Time (ms) P1 Priority P2 P3 P4 P5 For each of the following CPU scheduling algorithms, determine the turnaround and average waiting time for each of the process :- a. Shortest remaining Time First b. Shortest Job First C. Priority Scheduling (Both pre-emptive and non-preemptive) d. Round Robin (quantum is 1 ms)
C language show all work
1. [50 pts] Given the following set of processes, with arrival times, priorities, and the length of the CPU burst in ms: Priority Arrival Time Burst time Process P1 P2 P3 P4 4. 3 2 0 0 10 (Note: lower number means higher priority, processes P1, P2, P3, and P4 arrive at the same time, in the given order). a. Draw a Gantt chart showing a FCFS scheduling algorithm. b. Draw a Gantt chart showing...