Question

The following kinetic data were obtained for the reaction A $\rightarrow$ B

Time(t) (hrs) 0 2 4 6 10

[A] (M) 1.240 0.775 0.564 0.443 0.310

Determine the reaction order, the rate constant, and the time (t_1/2) at which [A]= 1/2[A]_o = 0.62M

b.) A biological molecule undergoes a reversible interconversion between its trans and cis forms with first-order reaction rate constants k₁(forward) and k_-1(reverse). the following kinetics results were obtained starting with 10mM of the pure trans form until equilibrium was achieved at t = $\infty$

Time(t) (s) 0 2.00 600 1000 $\infty$

[trans] (mM) 10.0 6.71 3.42 2.16 1.38

Determine k₁, k_-1 and the equilibrium constant K_eq from these data

Answer 1

The following kinetie data were obtained for the reactiom AB Time(t) (hrs)024610 A] M 1.240 0.775 0.5640443 0.310 Determine the reaction order, the rate constant,nd thet ()at waich A] 12A.-0.62M [A] versus t inear for a zero order reaction) ln [A] versus t (linear for a 1" order reaction) · .1[A) versus t (linear for a 2 order reactioa) Here we got linear line [A] versust means it is a zero order recation t1/2-[A]o 2k For a zero order reactio ate-k (-slope of line) Slope of recatioo-0.1055 k-(0.1055) - +0.1055 Given that (A)-1/2A-0.62M Tbus [A-1.24 M 1/2-1.24/2 0.1055 5.876 brs