Sodium cyanide reacts with 2-bromobutane in dimethylsulfoxide to form a substitution product....
because it is 3° carbon shouldnt it be an SN1 reaction? even though it is in a aprotic solvent with a strong Nu? Sodium Cyanide reacts with 2-bromobutane in dimethylsulfoxide to form a substitution product. Identify the configuration of the 2-bromobutane structure shown below. Then draw the substitution product formed when this enantiomer reacts with NaCN in DMSO, and indicate the stereochemistry of the product. O O (R)-2-bromobutane (S)-2-bromobutane Use wedge-and-dash bonds to show stereochemistry, and show explicitly the hydrogen...
Identify the major product(s) in the reaction of (R)-2-bromopentane with sodium cyanide in DMSO. Please draw the correct answer choice with its stereochemistry. 6) Identify the major product(s) in the reaction of (R)-2-bromopentane with sodium cyanide in DMSO. Please draw the correct answer choice with its stereochemistry. A) B) C) D) (S)-2-cyanopentane racemic mixture of 2-cyanopentane (R)-2-cyanopentane trans-2-pentene
In the substitution reactions below, draw the major product in the box provided and indicate in the small box whether the reaction is SN1, SN2, or neither. Be sure to show all stereochemistry. If more than one enantiomer is produced, write "+Enant" in the box with the product. [10] Product SN1/SN2/Neither NaCN Br DMSO NaOEt EtOH Br NaOMe MeOH NaOH Expensive Acetonitrile CH,Br DMF Nat
When 1-bromobutane reacts with sodium tert-butoxide (the conjugate base of tert-butyl alcohol) the major product is the elimination. Is this E1 or E2? Show the product Based on the information given in the problem, what was the key factor that changed the changed the major product from substitution to elimination?
Draw a structural formula for the substitution product of the reaction shown below. OCH + Br Nac Na OCCHE DMSO DMSO = dimethyl sulfoxide • Use the wedge/hash bond tools to indicate stereochemistry where it exists. • If more than one stereoisomer of product is formed, draw both. • Separate multiple products using the + sign from the drop-down menu. • Products that are initially formed as ions should be drawn in their neutral forms. We were unable to transcribe...
Draw the major E2 reaction product formed when cis-1-chloro-2-ethylcyclohexane (shown below) reacts with hydroxide ion in DMSO. DMSO is just a solvent and plays no role in what product is formed. Draw the product as a planar cyclohexane skeletal structure (framework provided). CHз HO ..HAH Ý CH2 CI DMSO Ń HH ! H 7 Hint Previous Check Answer Next Exit
Draw the major E2 reaction product formed when trans-1-chloro-2-ethylcyclohexane (shown below) reacts with hydroxide ion in DMSO. Draw the major E2 reaction product formed when trans-1-chloro-2-ethylcyclohexane (shown below) reacts with hydroxide ion in DMSO.
Draw the structure of the product that would be formed when 1-butanol reacts with sodium hydride, then 1-bromoethane. X Incorrect. Draw the structure of the product that would be formed when 1-butanol reacts with sodium hydride, then 1-bromoethane. H, no Edit Click if you would like to Show Work for this question: Modify Show Work SHOW HINT
Compound X, C8H17Cl, is a chiral product of the radical chlorination of 4-methylheptane. X reacts in SN2 fashion with NaI in acetone to form Z, C8H17I. When the reactant is the R-enantiomer of X, only the R-enantiomer of Z is formed. Draw a structural formula for X; do not show stereochemistry.
Draw the major E2 reaction product formed when trans-1-chloro-2-ethylcyclohexane (shown below) reacts with hydroxide ion in DMSO. DMSO is a solvent and plays no role in what product is formed. Draw the product as a planar cyclohexane skeletal structure (framework provided). н ., сн. H CH₃ HO H H H CH2 Vlci DMSO HH 7 Hint Previous Check Answer Next Exit