1. (25 points) Given the recurrence relations. Find T(1024). 2 T(n) = 2T(n/4) + 2n +...

Question

Question

1. (25 points) Given the recurrence relations. Find T(1024). 2 T(n) = 2T(n/4) + 2n + 2 for n> 1 T(1) = 2

Answer 1

Answer #1

ANSWER:

Code:

# Python code
def T(n):
if n==1:
return 2
else:
return 2*T(n/4)+2*n+2

# Testing
print(T(1024))

4094.0 ...Program finished with exit code 0 Press ENTER to exit console. I

Answer:

T(1024) is 4094

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Answer 2

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