Question

(8) Solve the equation and find exact solutions. log2 (x + 1) = 1 - log2 (x - 1)

Answer 1

This is the required solution.

Soph Given that, log (x+1)= 1-log (3) we have to solve the given equation, ire dog, (x+1)=1-log, (x-1) & log₂ (x+1)+ log (x-1) = 1 ng log (2+1) (x-1) = 1 {olog a + logb = logab} & log (22-1) = 1 > (22-1)=31 { loga = c + a=66} & x²-1 =3 es x²-420 - 19 - 2)(x+2) =0 3.2=~2,2 so the solution of equation are - 2 and 2.