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These answers are correct. cant seem to get to them though.
3) The 0.15-kg ball is released from position A with a velocity of 3 m/s and swings in a vertical plane. 1.2 m 0.8 m 3 m/s a.
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Answer #1

1.2m h 1:2 (1-60560) = 12 (1-1) .6m 3 ms 10 Igravity DKE am (vy 2-VA) - high = 9.8 x 6 = 1 (V, 2 - 32 ) A TL m = 0.15 kg > U

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