Question

Graph the following lines: Be sure to state the slope, x and y intercepts in coordinate form a) y = 2x + 3 b) y 2 c) 2x + 6y = 24

Answer 1

Answer: Page-1 we have, Y= 21+ 3 first find a coordniate points a but any value on the equation is line & then find y eso for that of X=0 وه ره و : 23 (0,3) but xzo in equation is : we get y = a1 + 3 = a (0) + 3 y = 0 + 3 est coordinate point Now, but yao we get Y=2x+3 on line cis is SO 1 0 = 2X + 3 2-3 3 =-1.5 on Now , Then we . + and coordinate point line si is (-1.5,0) plot point (0,3) & (-15,0) & goin them a line whose equation is y= 22+3 Graph get 3 (013) (4.90. -4-3 134

x & g intercept page-2 to find se intercept , put y20 in equation rij & get the value of x. We find the value of earliear by beeting х. yao, so X-1.5 x intercept is at (-1.5,o) to find y intercept , but x=0 the value of y find the value of 3 y y intercept is at (0,3) in equation ci & get by puting x=0,80 earliar we on line ,so are Slobe Since point (-1.5,oo ze (013) slope of line is a Yo-Y, xg-x, 3-0 0-(-1.5) - 1.5 (6) We have y = 1 x -2 2 on line cii SO 7 line cis is cord) to find find two points first but x=0 in ii y = 16x-2= 44(0)-2 1st coordinate point on similarly but y=0 in y = 1, x-2 o-tx-2 هک و دا)

4x=2 Page-3 Xog* 4 = 8 and coordinate point on line cis is (8,0) Now , graph then Join them & we get plot point (0,2) & (810) line whose equation is y=46x-2 a (810) HHH ---+-543 11+i 45678 -57609-7) on line , so Slobe. since points (0-2) & (8,0) slope of line= Ia-y, 0-(-4) eg-, 2 z I 4 8-O 8 x=8 that we get in intercept: but y=0 quation sij & solue earliar. har interccht is (810) at

Page-4 get y = -2 that we y intercept: but x=0 in equation & we solue y intercept is at (0-2) earliar so we have 21t64 =24 64 = = 24-2x =-2x + 24 y = -axt 24 6 - 27 +24 y=-1&x+4 si y point on line as on line cij , but x=0 to find & we get y=-13 8+4= -7/10)+4 line a is 0,4) on y =4 1st Coordiate point to find and point y=-3x+4 0=-1&xtu on line cis but yao & we get - 1/x = ..-4 -=-4 X 3 --12 =12 on and coordinate point line cij is (12,0)

graph : plot points get % &(12,0) (014) page-s then goin them & y=-34+4 we a line whose equation is 8 4 1008-6.42 ta 2724 6 10 14 14 16 Irudo Slobe: since points (0,4) & (12,0) slope : 42-4, 0-4 lg-X, are on line ,so - -4 12 -1 Id-o ao we will get I = ld that We earliar, x & y intercept: x intercept: but yao in equation di solue 80 x intercept is at 1(120) y intercept: in equation ni & that y intercept is but We will get y=4 we So solue earliar, at I co.4)