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The decomposition of N2O5 in carbon tetrachloride proceeds as follows: 2N2O5→4NO2+O2 The rate law is first...

The decomposition of N2O5 in carbon tetrachloride proceeds as follows:

2N2O5→4NO2+O2 The rate law is first order in N2O5. At 64*C the rate constant is 4.82 ×10^−3s^−1

The rate law is 4.82x10-3s-1 [N2O5]

The rate of rxn when [N2O5]=2.40x10^-2 M is 1.16x10^-4 M/s

What happens to the rate when the concentration of N2O5 is doubled? What about halved?

The answers are NOT 9.64x10^-3 and 2.41x10^-3 M/s

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Answer #1

a) if conc concentrati on of N2Ojis doubled rate of reaction(i)-1. 16x 10.4M/s conc [N205]C)-2.40x 102M if C 2x2.40x102M then

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