Percent yield=(actual yield/theoritical yield)100
Actula yield = 2.5kg
step(1) Calculation for theoritical yield
mass of CaF2= 6.15kg
we know that ,
Mola mass of CaF2= 78.07 g/mol
Molar mass of HF = 20.1g/mol
From the stoichiometric of chemical reaction
1mol of CaF2 produced 2mol of HF
Or
78.07 g CaF2 (i.e mass of 1mol CaF2 ) produced 2(20.1)g HF (i.e mass of 2 mol HF)
78.07 g CaF2 produced 40.2 g HF
Or
70.07kg CaF2 produced 40.2kg HF
So,
1.0kg CaF2 produced (40.2/70.07) kg of HF
So,
6.15 kg of CaF2 produced (40.2/70.07)6.15kg of HF
theoritical yield of HF = (40.2/70.07)6.15kg
Theoritical yield of HF = 3.53kg
Hence,
Percent yield =[ (2.5kg)/(3.53kg)]×100
PERCENT YIELD = 70.85%
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