Consider the linear second-order PDE for u = u(x, y), 2uxx – 3uxy – 2uyy =...
b) i. Form partial differential equation from z = ax - 4y+b [4 marks] a +1 ii. Solve the partial differential equation 18xy2 + sin(2x - y) = 0 дх2ду c) i. Solve the Lagrange equation [4 Marks] az -zp + xzq = y2 where p az and q = ду [5 Marks] x ax ii. A special form of the second order partial differential equation of the function u of the two independent variables x and t is given...
Consider the following second order PDE Uit – 9Uxx = 0, 0<x< < t > 0, (A) and the following boundary value/initial conditions: Ux(t,0) = uſt, 5) = 0, t>0, u(0, x) = 44(0, x) = 4 cos’ x, 0<x< (BC) (IC) for the function u= u(t, x). a. (5 points) Find ordinary differential equations for functions T = T(t) and X = X(x) such that the function u(t, x) = T(t)X(x) satisfies the PDE (A). b. (5 points) Find...
Show that the following PDE for u(x,y) is linear in u and homogeneous. ди ду ди = 3- дх Ә2 и + sin(у) дх2
1. Let p(x), a(x) and B(x) be three functions of r. Consider the PDE of u(r, t): PEx) at (a) (10 pt) Show that the method of separation of variables works only if ρ(r) equals to a constant. (b) (10 pt) Assumefor some constant c. Show that the spatial equation (the differential equation about the spatial variable r) is of Sturm-Liouville type. B(z)
1. Let p(x), a(x) and B(x) be three functions of r. Consider the PDE of u(r, t):...
What type of PDE is this? Solve PDE using separation of variables (show all the work and logic) 05 x u(x,0) 4sin(37r), u,(x,0) 2sin(57) 0sx 1,t 2 0
More details pls
Consider the PDE 2u, - 3uy = 0 where u = u(x,y). It can be shown (you don't have to do it) that product solutions to the PDE take the form u(x, y) = X(1)Y(y) = Cetrefty, (1) where C and can be any pair of constants. Here is what you need to work on: First, find infinitely many solutions to the PDE that look different from 1. Make sure to mention which method you used, if...
14 points Consider the following equation : PDE: u+ 0 ,0<x <1, 0<y <1 BCs: u(0, y)= 0, u (1, y ) = 0 ,0<y <1 ICs: u (x,0)=0, u (x,1)=2 ,0<x <1 a) Using the PDE and the boundary conditions write the form of the solution u (x ,t) b) Now apply the initial condition to solve for the unknown coefficients in the solution from part (a)
14 points Consider the following equation : PDE: u+ 0 ,0
=T 20 marks) Consider the following PDE with boundary and initial conditions: U = Upx + ur, for 0<x< 1 and to with u(0,t) = 1, u(1,t) = 0, u(1,0) = (a) Find the steady state solution, us(1), for the PDE. (b) Let Uſz,t) = u(?, t) – us(T). Derive a PDE plus boundary and initial conditions for U(2,t). Show your working. (c) Use separation of variables to solve the resulting problem for U. You may leave the inner products...
9. Consider the beam PDE for the transverse deflection u(x, t) of an elastic beam Utt + Kurz = 0 for 0 < x <L (30) where K > 0 is a constant. Suppose the boundary conditions are given by (31) u(0, t) = uz(0,t) = 0 Uwx (L, t) = Uzzz(L, t) = 0 (32) and the initial conditions are (33) u(x,0) = (x) u1(x,0) = V(x) (34) Use separation of variables to find the general solution to the...
statisfied the PDE Suppose that λ-λ 1,22 are constants such that u(x, y)-F(x + λy) 24 u(x,y))-10 ya for any twice-differentiable function of one variable F(s) Suppose also that λ1 λ2 , enter the values of λ 1, λ2 in the boxes below. 6 2 Hence the soution will be of the form Solve the PDE with the initial conditions u (x, 0)-5 sin (a), lty (x,0)-0. Enter the expression for u(x, y) in the box below using Maple syntax...