Question

9. Consider the beam PDE for the transverse deflection u(x, t) of an elastic beam Utt + Kurz = 0 for 0 < x <L (30) where K > 0 is a constant. Suppose the boundary conditions are given by (31) u(0, t) = uz(0,t) = 0 Uwx (L, t) = Uzzz(L, t) = 0 (32) and the initial conditions are (33) u(x,0) = (x) u1(x,0) = V(x) (34) Use separation of variables to find the general solution to the PDE. Make sure that your eigenfunctions satisfy the boundary conditions. You will not be able to find the eigenvalues in closed form, but instead derive a condition that implicitly defines the eigenvalues. Simplify this condition as much as possible.

Answer 1

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