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You are playing poker, and your hand currently holds 3 cards that all are aces. You...

You are playing poker, and your hand currently holds 3 cards that all are aces. You are then drawing two more cards. What is the probability that you will get a full house (3 of one kind and two of another)?

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Answer #1

probability that you will get a full house given first 3 cards are ace =P(first card is any card except ace from rest of 49 cards and second card is of same rank as of first from rest of 48 cards) =(48/49)*(3/48)=3/49 =0.061224

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