Question

An electromagnetic wave is incident on an interface between two materials at Brewster angle. The normal of the interface is a = -0.8âx + 0.6ây and the electric field of the wave is (T) = (9âx – 22.5ây)e-j(4x+1.6y) V/m. a) Find the Brewster angle. b) If ni = 3.0, determine the value of nt. c) The reflected field Ę(ř). d) (Optional, extra points) The transmitted field Ęt (ñ).

Answer 1

Answers P9N01 → A electromagnetic wave Predent between two materiale nterface R À = -0.8âx + o Gên a clenteric field wave is & (P) = (aax - 22.5ây) or (ext 1:64) was Berpuestos angles Angle through in total transmission no reblection mg+10 q=0 n2 = n = 1207 lin, a no Empresim of above . [ 8, (x) = Erie "Cart - 152) ax vers Ep(x) = En e swt - than wan Ei(r) & (98 - 22-say) && (us +164) un [B-k = Sa+86) 516 +2.56 ß = 518:56 radlom [. B = 4.308 rlm Priteerbace vedo ô = -6.8@ge +0.664 E = to elut - (or de t By ay of Bear)

€ = {o el lect-tis), & hoes Cut-off von pg. Nora B = 4.308 & = (Egan -2g5@y) e lloge te oy viras Gara & slot - (-0.82, +0.6@y) um - → from can of $ = Cas № 84 gѕР№9 Coco too every tas Ost. Bu 1. Bra stan" () Qub, Get = 188 Mar (617) 884 = 1800-tam (364) Olet = 180° ~ 36.86 Outi = 143.139 | .. Brewster angle is 143.130

Pg. Not 3 D.E=Nara to go anyone hoert E fit ut 107 = Sert = ni This na Jux 26 x 7² x 10 x 1 2x G XOT n = 404 R hiexon = tu ( n = 125.652 @, seblected field & Cry ng ane = 105612 = LOT medlingen, + Mo a lavor]

pg.no: 4 Reblation coelbitsent to co r = nao; - n, Coset ne Cos do to, Cast Foco : . Coser = n, Coset=0 Mg Casto = n Cosat Cost Cos De transmitted field (P) & () = TE (A) TE it r= 14 he caso, rn, Cosa Cos Go ton, Coset TE Coser th, of the Cosophe Cofet na to, Goso Te ana Caso he Coso, tn, Casey T= - an, Losa. megsco (int a Comet Coso Cosen

Pg. Nors T= 2 = T = 100% T=1 tim wave totaly transmitted £4 (8) = 6:6) - (99 - 29.5@y) erCox +1-64). /mo)