Locate the centroid X of the shaded area, then locate centroid Y of the shaded area.
Locate the centroid x¯ of the area. Take a = 6 m . D zY X a
2) Locate the x coordinate of the centroid of the shaded area. 12" 3 6" 4 ーし
3. Locate the centroid x of the shaded area. y = a sin a (TT
4. (30 pts) Locate the centroid (x,y) of the composite area and determine its moment of inertia about the x-axis. 6 in. 3 in. 3 in. 3 in. -3 in. --- 3 in.-
Locate the centroid of the shaded area between the two curves. Locate the centroid of the shaded area between the two curves.
Version Name: 4. Locate the centroid (2,7) of this area using BOTH (a) integration and (b) the Composite Method. y = 2.5x + 3 3 m
Locate the centroid (x, y) of the shaded area. Then find Ix and Iy.Lifesaver given to correct answer with all work shown.
Locate the centroid (x, y) of the shaded area. 6in. Find the area moment of inertia of shaded area around x-axis and y-axis. 6 in.
Question 3 26 pt Locate the centroid (i,y) of the shaded area (26 Marks). 0.6 m 3 m у 1.5 m 3 m 1 m Important Table: Geometric Properties of Line and Area Elements Centroid Location Centroid Location Area Moment of Inertia L-20 sin 20) 1,- 20 453/take ometric Properties of Line and Area Elements Centroid Location Centroid Location Area Moment of Inertia у -L-201 - 1.- (0-sin 20) 1,=+c0+ sin 20) rsine "'" Circular arc segment Circular sector area...