Question

12:10 att-subnet1: Attempt 1 192.168.10.128 192.168.10.130 Question 2 -/10 Given: (class C subnetting problem) Network address 192.168.10.0 Subnet mask: 255.255.255.224 What is the broadcast address of the third subnet? (Hint: Watch the video tutorial) 192.168.10.96 192.168.10.95 192.168.10.63 192.168.10.64 0 of 2 completed Save for Later Submit

Answer 1

Question 1:
  
Answer :    Option 4 (192.168.10.130)

Explanation:
Given a Class C
Ip : 192.168.10.0
Sm : 255.255.255.128

In Class C ,24 bits for netowrk Id and 8 bits for host .

Subnet mask in bits : 11111111.11111111.11111111.10000000
From 8 bits 1 bit is chosen for subnetting part(Putting all 1's in network id gives subnet mask)
The first network starts with 0 and second network starts with 1.

Ip addresses of Second subnet.
192.168.10.128 (192.168.10.10000000)
192.168.10.129 (192.168.10.10000001)
192.168.10.130 (192.168.10.10000010)
.
.
.
The first address is used as subnet id ,so it is not useful address .
so,the second useful address is 192.168.10.130.

Questin 2:

Answer: Option 2 (192.168.10.95)

Explanation:
Sm in bits : 11111111.11111111.11111111.11100000
Three bits from host taken for subnetting (In class c network id 24 bits,host id 8 bits)
Subnets are :
192.168.10.00000000
192.168.10.00100000
192.168.10.01000000

Third subnet is 192.168.10.010.....
To get Broadcast address put all 1's in Host id.i.e 192.168.10.0101111

192.168.10.95(in decimal)