Question

. Calculate the velocity, momentum, and wavelength of a) a photon of 50 eV energy, b) an electron accelerated through 50 Volts, and c) a neutron with kinetic energy of 50 eV.

Answer 1

Velocity of photon = c = velocity of light wave length lambda = 12400/E(e v) A degree = 12400/50 e v lambda = 248 A degree For photon, Energy E = c p p = E/c = 50 e v/3 times 10^8 p = 50 times 1.6 times 10^-19/3 times 10^8 p = 2.7 times 10^-26 kg m/s Election diffraction lambda = squareroot 150/E(e v) A degree = squareroot 150/V(volt) A degree = squareroot 150/50 = squareroot 3 lambda = 1.71 A degree Re Broglie wave length lambda = h/p implies p = h/lambda = 6.6 times 10^-34/1.71 times 10^-10 p = 3.8 times 10^-44 k g m/s p = m vs v = p/m = 3.8 times 10^-44/9.2 times 10^-31 v = 0.41 times 10^-13 v = 4.1 times 10^-14 m/s Neutron diffraction lambda = squareroot 150/E(e v) = squareroot 150/50 = 1.71 A degree momentum p = h/lambda = 6.6 times 10^-34/1.71 times 10^-10 p = 3.8 times 10^-44 kg m/s p = m
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