Question

Problem #1 an object of mas: kg) sits on a frictionless range of length 2 meters, at an angle of 30. The range sit on top of a tablee of height 2 meters. tom=3kg 2mitins a) where does object hit the floor? b) Total time from start to finish? C) What is the speed & velocity when it hits the Floor?

Answer 1

Solution mass = m = 3kg - E - Irene vi (as table , VOY now has uelocity acquire at the edge of the - using conservation of mechanical energy ngh a thua where in is the height of the range, v= Vage v= 52x9.8xe where ch= zsin 30o = 2x} =1 v 19.6 ms. halm v=Jzxq8x1 = [V = 4.43 m/s

V loso Vsina Usino Don Now at the edge of tralale the components of the velocity are as shown above. Now, to bind horizontal distance = 'R' R = vcasoxt where 't' is time taben to fall from the edge of table using S=ut that? 2=vSin 30° at ttxa18t? 2. = 4.43*+ ** + 4.942 4.9+? + 2.215 # -2 -07 where S= height of tabek = am. solving above equation we get t=0.45178 and t= -0.9048 dis carding -ve root It = 0.45178

o Range =R= vcasoxt R = 4:43 * COS 30° * 0.4517 JR=1.73m) (ee) Total time =T=? off the T= time of wedge + time age . . to fall tabele table mgsina 3 от Now, Along the wedge , a=gsind, S=2m u=0 using is= ut that? 2= 0 + 4xg singoº * + 2 2x 9.8 x įxt? 2= 4.qxt? t- saone - 0.9048 Total time = 0.904 + time to fall off the S table 0.904 t 0.4517 = 1.368. 2= 8

& Total time = 1.36s. cc. As in edge of as shown part cal the velocity at the the talk was v= 4:43mle directed below NA > Vcoso vsino table am - When it will hit the ground the horizontal velocity will remain same that is caso as there is no horizontal force. But vertical Velocity = V = usino + gt v'- v sina + gt v= 4.43* sin selt 9-88 time of fall from table v'= 4:43 +9.88 ousia uz 2.22 + 4.43 = 6:6.5 Tv'=665 mis T=final vertical - Velocity. Now. Net speed = Juiz + vacaso = Speed on reathing ground = 7.7ml - 7.7m/s %

velocity of reaching ground - reasoi vi ĵ ū - 3.84 î - 6.65j7 aud - and speed = 7.7m/ aprox.