Question

The solid shaft shown in Figure 5.1 is made of an aluminium alloy 6061-T6, assumed to be elastoplastic with G = 26 GPa and yield shear strength ty= 140 (a) i. The torque T required to initiate yielding The radius of elastic core if the torque T is increased 15% of case (1) Angle of twist at the free end to reach case (ii) (8 marks) 1.2 m 36 mm

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Answer #1

1)Use the formula,

  Tall,--J equation (1)

Where Tallw-Ту- 140Mpa

radius r=18 mm

Calculate the polar moment of inertia   TU14 3.14 × 364 32 = 164812·32mm4

Now, from equation (1)

T×18 164812.32

T- 1281873.6Nmm

This is the torque required to initiate yielding.

(2)If the Torque is increased by 15% of case (1),

12-1281873.6 × 1.15-1474 154.64N772 772

Using equation (1) to prevent yielding,

Tr Tall,--J 1474 154.64 × d/2 140 =

Solving one will get d=37.17 mm thus

radius r=d/2=18. 585 mm

(3) Finding the Angle of twist for the case (2)  

Use  rac{ au}{r}=rac{G heta }{L}

140 260006 18.585 1200

Solving we will get, e-0.35rad

or 180 1.98 idegrees 00.35rad

  

  

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