Question

can someone please help and explain this ?

em boll cups second in the id mass of koupries as seen in the sample. context of this sample. Temp ( pare food in the Tiger Café. Mary notices that sales Yuit cups seem to vary widely from day to day. This is a Dlem because preparing too many cups results in wasted fruit and making too few results in lost sales. She decides that the daily weather may have a strong association with demand. Mary chooses 5 days at random from last semester and pairs each day's high temperature with the number of fresh fruit cups sold each day. 150 of Cups a. Standardize the data set above, in other words find the sample mean, sample standard deviation and each z-score for the table. Show all of your work b. Calculate the correlation coefficient, T, from the standardized data set. Show work!

Answer 1

Soln

From the data, we calculate the mean and standard deviation of the two groups.

Mean (X bar) = Sum of Values /n

and

Σ-x) n 1 σ=

We Calculate Standardised Value as:

Temp Standardized = (X – Mean) / (Std Dev/n^1/2)

	Temp	No Cups	Temp Standardized (X)	No Of Cups Standardized (Y)
	89	150	3.17	2.67
	52	85	-3.00	-2.89
	72	136	0.33	1.47
	65	101	-0.83	-1.52
	72	122	0.33	0.27
Mean	70.00	118.80
Std Dev	13.40	26.17
n	5	5

b)

Correlation Coefficient

	Temp Standardized (X)	No Of Cups Standardized (Y)	XY	X2	Y2
	3.17	2.67	8.45	10.06	7.11
	-3.00	-2.89	8.68	9.03	8.34
	0.33	1.47	0.49	0.11	2.16
	-0.83	-1.52	1.27	0.70	2.31
	0.33	0.27	0.09	0.11	0.07
Total	0.00	0.00	18.98	20.00	20.00

n(Σxy)-Σx)(Σy) VIηΣx-Σx2 [ ηΣy? - (Σy?

Using the above formula and values, we get

r = 0.949