Question

The atomic mass of 5626Fe is 55.934939 u, and the atomic mass of 5627Co is 55.939847 u.

How much kinetic energy will the products of the decay have?

Express your answer with the appropriate units.

Answer 1

Write the expression to calculate the mass defect. Am- m(Co-m(Fe) (55.939847 u)-(55.934939 u) 4908x10% u Calculate the binding energy -(4.90%10% u)(3x108 m/s) Convert the above energy in MeV. 2 Г931.5 MeV( 1 (4.908x10% u)(3x108 ms) E, 27 931.5 MeV |(4.908 x 10% u)(3x108 m's 3 x10 m/s 4.571 MeV

Calculate the energy carried by the positron and the electron = 2(9.11×10-31 kg)(3x108 m/s*) = 1.63×10-15 J Convert the above energy in eV. 1 J 1.023 MeV Calculate the total kinetic energy of the product. K-E 4.571 MeV-1.023 MeV 3.55 MeV