Question

(a) Find 6,-x2). answer: (b) Determine the rejection region for the test of H. : (H1 - H2) = 2.1 and H,:(H1 - H2) > 2.1 Use a
(1 point) Randomly selected 150 student cars have ages with a mean of 7.9 years and a standard deviation of 3.4 years, while
(1 point) There is a lot of interest in the relationship between studying music and studying math. We will look at some sampl
1 point) Random samples of resting heart rates are taken from two groups. Population 1 exercises regularly, and Population 2
0 0
Add a comment Improve this question Transcribed image text
Answer #1

Students cars-----------------------------

Ho :   µ1 - µ2 =   0                  
Ha :   µ1-µ2 >   0                  
                          
Level of Significance ,    α =    0.04                  
                          
Sample #1   ---->   sample 1                  
mean of sample 1,    x̅1=   7.90                  
standard deviation of sample 1,   s1 =    3.40                  
size of sample 1,    n1=   150                  
                          
Sample #2   ---->   sample 2                  
mean of sample 2,    x̅2=   5.00                  
standard deviation of sample 2,   s2 =    3.30                  
size of sample 2,    n2=   65                  
                          
difference in sample means =    x̅1-x̅2 =    7.9000   -   5.0   =   2.90  
                          
pooled std dev , Sp=   √([(n1 - 1)s1² + (n2 - 1)s2²]/(n1+n2-2)) =    3.3703                  
std error , SE =    Sp*√(1/n1+1/n2) =    0.5005                  
                          
t-statistic = ((x̅1-x̅2)-µd)/SE = (   2.9000   -   0   ) /    0.50   =   5.795
                          
Degree of freedom, DF=   n1+n2-2 =    213                  
t-critical value , t* =        1.7591   (excel function: =t.inv(α,df)            
Decision:   | t-stat | > | critical value |, so, Reject Ho                      
  
                          
B. Yes.               

Degree of freedom, DF=   n1+n2-2 =    213              
t-critical value =    t α/2 =    2.0664   (excel formula =t.inv(α/2,df)          
                      
pooled std dev , Sp=   √([(n1 - 1)s1² + (n2 - 1)s2²]/(n1+n2-2)) =    3.3703              
                      
std error , SE =    Sp*√(1/n1+1/n2) =    0.5005              
margin of error, E = t*SE =    2.0664   *   0.5005   =   1.0342  
                      
difference of means =    x̅1-x̅2 =    7.9000   -   5.000   =   2.9000
confidence interval is                       
Interval Lower Limit=   (x̅1-x̅2) - E =    2.9000   -   1.0342   =   1.8658
Interval Upper Limit=   (x̅1-x̅2) + E =    2.9000   +   1.0342   =   3.9342

--------------------------------Heart rate-----------------------

Ho :   µ1 - µ2 =   0                  
Ha :   µ1-µ2 <   0                  
                          
Level of Significance ,    α =    0.075                  
                          
Sample #1   ---->   sample 1                  
mean of sample 1,    x̅1=   69.57                  
standard deviation of sample 1,   s1 =    1.99                  
size of sample 1,    n1=   7                  
                          
Sample #2   ---->   sample 2                  
mean of sample 2,    x̅2=   73.50                  
standard deviation of sample 2,   s2 =    3.82                  
size of sample 2,    n2=   8                  
                          
difference in sample means =    x̅1-x̅2 =    69.5714   -   73.5   =   -3.93  
                          
pooled std dev , Sp=   √([(n1 - 1)s1² + (n2 - 1)s2²]/(n1+n2-2)) =    3.1097                  
std error , SE =    Sp*√(1/n1+1/n2) =    1.6094                  
                          
t-statistic = ((x̅1-x̅2)-µd)/SE = (   -3.9286   -   0   ) /    1.61   =   -2.441
                          
Degree of freedom, DF=   n1+n2-2 =    13                  
t-critical value , t* =        -1.5299   (excel function: =t.inv(α,df)              

p-value =        0.014856   [ excel function: =T.DIST(t stat,df) ]               
Conclusion:     p-value <α , Reject null hypothesis                      
                          
D. Reject Ho.                       

THANKS

revert back for doubt

please upvote

       

Add a comment
Know the answer?
Add Answer to:
(a) Find 6,-x2). answer: (b) Determine the rejection region for the test of H. : (H1...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • (3 points) Suppose that we are to conduct the following hypothesis test. Ho H980 H1: μ...

    (3 points) Suppose that we are to conduct the following hypothesis test. Ho H980 H1: μ > 980 suppose that you also know that σ-: 200, n 100, 1020, and take α-: 0.01 . Draw the sampling distribution, and use it to determine each of the following A. The value of the standardized test statistic: Note: For the next part, your answer should use interval notation. An answer of the form -oo, a is expressed (-infty, a), an answer of...

  • Random samples of resting heart rates are taken from two groups. Population 1 exercises regularly, and...

    Random samples of resting heart rates are taken from two groups. Population 1 exercises regularly, and Population 2 does not. The data from these two samples is given below: Population 1: 71, 66, 71, 68, 67, 68, 68 Population 2: 75, 69, 72, 71, 72, 69, 69, 70 Is there evidence, at an ?=0.08 level of significance, to conclude that there those who exercise regularly have lower resting heart rates? (Assume that the population variances are equal.) Carry out an...

  • Math & Music (Raw Data, Software Required): There is a lot of interest in the relationship...

    Math & Music (Raw Data, Software Required): There is a lot of interest in the relationship between studying music and studying math. We will look at some sample data that investigates this relationship. Below are the Math SAT scores from 8 students who studied music through high school and 11 students who did not. Test the claim that students who study music in high school have a higher average Math SAT score than those who do not. Test this claim...

  • Find B. (1 point) Suppose that you are to conduct the following hypothesis test: 0 H...

    Find B. (1 point) Suppose that you are to conduct the following hypothesis test: 0 H 510 H1: μ 510 Но Assume that you know that σ = 80, n = 42, x = 493.2, and take α = 0.01 . Draw the sampling distribution, and use it to determine each of the following: A. The value of the standardized test statistic: 1.36 Note: For the next part, your answer should use interval notation. An answer of the form (-00,...

  • You wish to test the following claim (H1) at a significance level of α=0.005.       Ho:μ1=μ2       H1:μ1>μ2...

    You wish to test the following claim (H1) at a significance level of α=0.005.       Ho:μ1=μ2       H1:μ1>μ2 You obtain a sample of size n1=117 with a mean of M1=62.8 and a standard deviation of SD1=10.2 from the first population. You obtain a sample of size n2=114 with a mean of M2=57.5 and a standard deviation of SD2=12.8mfrom the second population. What is the critical value for this test? (Report answer accurate to three decimal places.) critical value = What is the...

  • Math & Music (Raw Data, Software Required): There is a lot of interest in the relationship...

    Math & Music (Raw Data, Software Required): There is a lot of interest in the relationship between studying music and studying math. We will look at some sample data that investigates this relationship. Below are the Math SAT scores from 8 students who studied music through high school and 11 students who did not. Test the claim that students who study music in high school have a higher average Math SAT score than those who do not. Test this claim...

  • You wish to test the following claim (H) at a significance level of a = 0.10....

    You wish to test the following claim (H) at a significance level of a = 0.10. How > H2 H:41 <12 You believe both populations are turmally distributed, but you do not know the standard deviations for either. You obtain a sample of size 11 = 11 with a mean of Mi = 66.6 and a standard deviation of SD = 20.9. You obtain a sample of size ng = 11 with a mean of M2 = 74.8 and a...

  • For the given data, (a) find the test statistic, (b) find the standardized test statistic, (c)...

    For the given data, (a) find the test statistic, (b) find the standardized test statistic, (c) decide whether the standardized test statistic is in the rejection region, and (d) decide whether you should reject or fail to reject the null hypothesis. The samples are random and independent Claim: <H2, a=0.01. Sample statistics: x = 1235, n = 30, X2 = 1205, and n = 60. Population statistics: 6 = 70 and 62 = 100. (a) The test statistic for ,...

  • You wish to test the following claim (H) at a significance level of a = 0.001....

    You wish to test the following claim (H) at a significance level of a = 0.001. H:M1 = H2 H:41 € M2 You obtain a sample of size n1 = 101 with a mean of M = 79.4 and a standard deviation of SD = 15.3 from the first population. You obtain a sample of size ny = 36 with a mean of M2 and a standard deviation of SD2 = 14.4 from the second population. What is the critical...

  • 15) Find the critical value that defines the rejection region for the following hypothesis test: Is...

    15) Find the critical value that defines the rejection region for the following hypothesis test: Is the average life expectancy of Americans more than 78.8 years? To test this claim, a sample of 400 Americans are studied, with an average lifespan of 79.4 years and a standard deviation of 3.9 years. Use a significance level of 0.05. A) 1.649 B) 1.645 C) 3.08 D) -1.649 E) None of the Above 16) A large software company gives job applicants a test...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT