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Email MyCarleton A stationary box of mass 5.3 is being pushed by a force 34 N at an angle 0 30° with respect to the horizonta

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Answer #1

Force F is acting at 30 deg ,which can be split into its components

Fcos30 acting in horizontal direction

Fsin30 acting vertically downwards

---------------------

Consider all vertical forces in the figure

Fy0

FN-FSin -mg

FN Fsin+mg

FN 34N sin30 5.3kg 9.81m/s

FN 34 sin30+5.3 9.81

FN = 68.993N

==========

Static Frictional Force =Static Frictional coefficient * Normal Force

N

fs=0.57 68.993N

is= 39.32601

ANSWER: ts=39N

===============

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