Question

Consider the circuit below. Assume le= Ic= 3.2 mA. Determine: O Vcc=16 V KO Cout 3 22 22 BAC = Poc = 160 toma 10 ka z 220 카 a) Voltage gain, Av (including RL) b) Peak AC output current (through the load): HOUT c) Ic(sat) (endpoint for DC loadline) d) VCE(off) (endpoint for DC loadline) e) ic(sat) (endpoint for AC loadline) f) VCE(off) (endpoint for AC loadline) g) Maximum undistorted peak output voltage, Vout h) Maximum possible efficiency assuming linear amplification

Answer 1

LE Im = 3.2 mA 26 mv = 0.12 S a) voltage gain Arc-gm* Rclre - 0.12 2.22.2 2.27 2.2 = -0.132 x 10 Ava - 132. Peak ac augue voltage = Voo = Aux Ving op = -132 x 10 mV Peak ac Vop = -1.320 V suflet cument Top = s -1.320 2.2 - mA P = -0.6 mA. c) Iccsat) - Vee 16 = 7.27 mA d) Vce colts = Vas 16 v