Question

= 30 m2, 1. (20 pts.). In the circuit shown in the diagram Rj = 10 m2, R2 = 0.02 , R3 = 0.01 , R Rs = 40 ml, R = 50 m2, Ry = 60 mA, and < = 100 V. A) (10 pts.) find the equivalent resistance for this circuit; B) (5 pts.) find the voltage and the current for the resistor Ri C) (5 pts.) find the electric power in the resistor R.

Answer 1

w WA 9 Given R = 10x103 R220.022 R3 I 0.02 Ry = 80x103 R к — цохоо R = 50x10²2 R7 = 60x1032 &= loov. Ry & R are 80 (RytRs) and in series Rat Rs = 70x108 2 = 0.07 Re are in parallel k that buites = stort odog - 100 + lo soto R & R are in series so R=RfR6 = 80g 7 +0.05 suo R₂ & Ř are in = 0.05875 2 parallel. for " at I + t = 0.02+0.05875. - KT Å - 0.05875 0.02 - 0.02% 0.05875 R'"- 0.02% 0.05875 - 0.02 + 0.05875 - = 0.014920 = 0.01492 R Rg & R are en series. Reg of cacuit = o R"+Rq+R = 0.0149+0.001 +0.06 = 0.0759 el B current through R = current en battery - Res - 100 0.0759 = 1817.5A & voir = 1817.500.001 = 1.31750] o power in Resistor Rq = {²Rq = (1317.5) ²x0.06 - 104148.37 watt / 1.3175V