wenyewer verwe Blank paper and calculator are allowed Question 17 of 2 1.6 points Save Answer...

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Answer 1

Answer #1

The energy stored in a capacitor is

$W=\frac{QV}{2}$

Now when we inserted dielectric medium of dielectric constant K then the energy stored

$W'=\frac{KQV}{2}=KW = 2*27=54 Joule$ So, the energy stored by the capacitor is 54 joule

Answer 2

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