The random variable Z denotes a standard normal random variable, Upper Z tilde Upper N left parenthesis 0 comma 1 right parenthesis. What is the standard deviation of Z?
Z is standard normal variable.
Z has standard normal distribution with mean = 0 and variance = 1
Z ~ N(0, 1)
Standard deviation is nothing but square root of variance.
Standard deviation of Z is 1.
The random variable Z denotes a standard normal random variable, Upper Z tilde Upper N left...
, Upper X 2, Upper X 3, and Upper X 4 are normally distributed random variables: Upper X 1 tilde Upper N left parenthesis 0 comma 0 right parenthesis, Upper X 2 tilde Upper N left parenthesis 0 comma 1 right parenthesis, Upper X 3 tilde Upper N left parenthesis 1 comma 0 right parenthesis, and Upper X 4 tilde Upper N left parenthesis 1 comma 1 right parenthesis. X1, X2, X3, and X4 are normally distributed random variables: X1...
Let z be a random variable having a standard normal distribution. Determine P left parenthesis minus 1.56 less than x less or equal than 1.56 right parenthesis.
Suppose T and Z are random variables. a. If Upper P left parenthesis Upper T greater than 2.57 right parenthesisequals0.04 and Upper P left parenthesis Upper T less than minus 2.57 right parenthesisequals0.04, obtain Upper P left parenthesis negative 2.57 less than or equals Upper T less than or equals 2.57 right parenthesis. b. If Upper P left parenthesis negative 0.36 less than or equals Upper Z less than or equals 0.36 right parenthesisequals0.28 and also Upper P left parenthesis...
Determine the area under the standard normal curve that lies to the right of left parenthesis a right parenthesis Upper Z equals 1.25 comma(a) Z=1.25, (b) Upper Z equals negative 0.86 commaZ=−0.86, (c) Upper Z equals 0.02 commaZ=0.02, and (d) Upper Z equals negative 0.78 .Z=−0.78.
4) Given that z is a standard normal random variable, find z for each situation The area to the left of z is .9750. The area between 0 and z is .4750. The area to the left of z is .7291. The area to the right of z is .1314. The area to the left of z is .6700. The area to the right of z is .3300.
4) Given that z is a standard normal random variable, find z for each situation (using excel): The area to the left of z is .9750. The area between 0 and z is .4750. The area to the left of z is .7291. The area to the right of z is .1314. The area to the left of z is .6700. The area to the right of z is .3300.
Assume the random variable x is normally distributed with mean mu equals 50 and standard deviation sigma equals 7. Find the indicated probability. Upper P left parenthesis x greater than 36 right parenthesis Upper P left parenthesis x greater than 36 right parenthesisequals (Round to four decimal places as? needed.)
Determine the area under the standard normal curve that lies to the left of (a) Upper Z equals 0.24 comma (b) Upper Z equals negative 1.75, (c) Upper Z equals negative 1.22, and (d) Upper Z equals 0.68.
Determine the area under the standard normal curve that lies to the left of (a) Upper Z equals 1.69 comma (b) Upper Z equals 0.36, (c) Upper Z equals negative 0.72, and (d) Upper Z equals 0.74. (a) The area to the left of Zequals1.69 is nothing. (Round to four decimal places as needed.)
For a Standard Normal random variable Z, calculate the probability P(-0.25 < Z < 0.25). For a Standard Normal random variable Z, calculate the probability P(-0.32 < Z < 0.32). For a Standard Normal random variable Z, calculate the probability P(-0.43 < Z < 0.43). Calculate the z-score of the specific value x = 26 of a Normal random variable X that has mean 20 and standard deviation 4. A Normal random variable X has mean 20 and standard deviation...