4) Given that z is a standard normal random variable, find z for each situation (using excel):
The area to the left of z is .9750.
The area between 0 and z is .4750.
The area to the left of z is .7291.
The area to the right of z is .1314.
The area to the left of z is .6700.
The area to the right of z is .3300.
There exists a function in Excel called NORMSINV(x) which returns the inverse of the standard normal cumulative distribution.
1.
=NORMSINV(0.9750)
1.959964
2.
=NORMSINV(0.475+0.5)
1.959964
3.
=NORMSINV(0.7291)
0.610093
4.
=NORMSINV(1-0.1314)
1.119798
5.
=NORMSINV(0.6700)
0.439913
6.
=NORMSINV(1-0.3300)
0.439913
4) Given that z is a standard normal random variable, find z for each situation (using...
4) Given that z is a standard normal random variable, find z for each situation The area to the left of z is .9750. The area between 0 and z is .4750. The area to the left of z is .7291. The area to the right of z is .1314. The area to the left of z is .6700. The area to the right of z is .3300.
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