Given that is a standard normal random variable, find for each situation (to 2 or 3 decimals).
a. The area to the left of z is 0.8
b. The area to the left of z is 0.981
c. The area to the right of z is 0.6045
d. The area between -z and z is 0.82
(Hint: Enter the positive z-value)
Hello Sir/ Mam
(a)
Using excel function, "=NORM.S.INV(0.8)", we get z-score= 0.8416
(b)
Using excel function, "=NORM.S.INV(0.981)", we get z-score = 2.0749
(c)
Using excel function, "=NORM.S.INV(1-0.6045)", we get z-score = -0.2650
(d)
Using excel function, "=NORM.S.INV(0.09)" and "=NORM.S.INV(0.91), we get z-scores -1.3408 and 1.3408 respectively.
I hope this solves your doubt.
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