Given that z is a standard normal random variable, find the z-score for a situation where...

Question

Question

Given that z is a standard normal random variable, find the z-score for a situation where the area to the left of z is 0.0901.

Answer 1

Answer #1

Solution :

P(Z < z) = 0.0901

To see the probability 0.0901 in the z table the cumulative z value is -1.34

P(Z < -1.34) = 0.0901

z = -1.34

Answer 2

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