1) molar mass of H3PO4 is 98g/mol
2) From one mole of P4 , 4 moles of H3PO4 can be obtained as per the stoichiometric equation
3) yield = 114 g
= 114/98
=1.1632 mol
4) According to the equations
1 mole of P4 produces 4 moles of H3PO4
moles of P4 that can produce 1.1632 moles of H3PO4 is
= 1.1632 x 1/4=
= 0.29 moles of P4
5) mass of P4 used in question 4 = 0.29 x 124
= 35.96 g
6) Out of 175 g taken from bottle of P4 only 35.96 g are P4 that reacted
mass percent of posphorus= mass of P4x100/mass of sample
= 35.96x100/175
= 20.55%
Need help on 5 and 6 Phosphoric acid, H_3PO_4, has some important applications. It can be...
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