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If the standard deviation of a normally distributed population is 60 and we take a sample of size 25, then what is the (stand
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\\Standard\;Deviation (\sigma)= 60
Sample size (n) = 25
Since we know that
\\Sample \;standard\;deviation(s) = \frac{\sigma}{\sqrt{n}} = 12.0



\\Mean (\mu)= 250
Sample size (n) = 25
Since we know that
\\Sample \; mean (\bar{x}) = \mu = 250.0


\\Mean (\mu)= 34 \\Standard\;Deviation (\sigma)= 5
Sample size (n) = 42
Since we know that
\\Sample \; mean (\bar{x}) = \mu = 34.0 \\Sample \;standard\;deviation(s) = \frac{\sigma}{\sqrt{n}} = 0.7715



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