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4. Show that lim -oxsin(1/2) = 0 by by appealing directly to the definition of limit. Recall that -1 < sin < 1. 5. Define a f
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Answer #1

To show lim xesin (+2) = 0 aro . We have to show every E>0, 7870 such that of lae1c 8 gines I de sine ulaz) -0,se ciel fcae )

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4. Show that lim -oxsin(1/2) = 0 by by appealing directly to the definition of limit....
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