send help for these 4 questions, please show steps Definition: The AREA A of the region...
(1 point) Definition: The AREA A of the region that lies under the graph of the continuous function f is the limit of the sum of the areas of approximating rectangles A = lim R, = lim [f(x)Ar + f(x2)Ax+... +f(x,y)Ax] 100 Wspacelin (a) Use the above definition to determine which of the following expressions represents the area under the graph of f(x) = x3 from x = 0 to x = 2. 64 A. lim 7100 11 i= B....
Week 1: Problem 21 Previous Problem List Next (1 point) Definition: The AREA A of the region that lies under the graph of the continuous function is the limit of the sum of the areas of approximating rectangles A - lim R. - lim (/(x1)Ar + ()Ar+...+(2.)A: () = 352 10. Using the above definition determine which of the following expressions represents the area under the Consider the function graph off as a limit. A. lim j7 ln() lo in...
-/2 POINTS SESSCALCET2 5.1.503.XP. The area A of the region that lies under the graph of the continuous function is the limit of the sum of the areas of approximating rectangles. lim Rn limf ax + 2)Ax + ... + X)x] Use this definition to find an expression for the area under the graph off as a limit. Do not evaluate the limit. FX) - VX,15* $ 12 A lim Need Help? Talk to Tutor
The area A of the region S that les under the graph of the continuous fun the areas of approximating rectangles sthis deinition to find an expression for the area under the graph of f as a The area A of the region S that lies under the graph of the continuous function is the limit of the sum of the areas of approximating rectangles Use this definition to find an expression for the area under the graph of f...
ssignment6: Problem 9 Previous Problem Problem List Next Problem (1 point) The area A of the region Sthat lies under the graph of the continuous function f on the interval (a, b) is the limit of the sum of the areas of approximating rectangles: A = lim (f(21)Ar + f(x2)Ax+...+f(xn)Ax] = lim f(x;)Az, n-> ng i=1 where Ax = b and Ti = a +iAr. The expression A = lim Itan(n) 7200 6n2 gives the area of the function f(x)...
Just need the answer to question 6 using the information provided in the block above question 5. Please be clear due to this being a multi-step problem. Thanks Let g(x) = 1- x and f(x) = x2 - 2x + 1 for Problems 5 and 6 below. 5. (a) Draw a graph of f(x) and g(x) on the same axes, and label their points of intersection. Calculate the area below g(2) and above the z-axis between I = 0 and...
(2 points) The area \(A\) of the region \(S\) that lies under the graph of the continuous function \(f\) on the interval \([a, b]\) is the limit of the sum of the areas of approximating rectangles:$$ A=\lim _{n \rightarrow \infty}\left[f\left(x_{1}\right) \Delta x+f\left(x_{2}\right) \Delta x+\ldots+f\left(x_{n}\right) \Delta x\right]=\lim _{n \rightarrow \infty} \sum_{i=1}^{n} f\left(x_{i}\right) \Delta x $$where \(\Delta x=\frac{b-a}{n}\) and \(x_{i}=a+i \Delta x\).The expression$$ A=\lim _{n \rightarrow \infty} \sum_{i=1}^{n} \frac{\pi}{8 n} \tan \left(\frac{i \pi}{8 n}\right) $$gives the area of the function \(f(x)=\) on...
only the ones highlighted and please show all steps. Finding Area by the Limit Definition In Exercises 47–56, use the limit process to find the area of the region bounded by the graph of the function and the x-axis over the given interval. Sketch the region. 47. y = - 4x + 5, [0, 1] 48. y = 3x - 2. [2,5] 49. y = x2 + 2, [0, 1] 50. y = 5x + 1, [0, 2] 51. y...
PLEASE SHOW WORK WITH CLEAR STEPS 11. f (x) 5- x2 Estimate the area under the graph from x1 to x 2 using three rectangles and right endpoints. Then improve your estimate by using six rectangles. Sketch the curve and the approximating rectangles. ее 11. f (x) 5- x2 Estimate the area under the graph from x1 to x 2 using three rectangles and right endpoints. Then improve your estimate by using six rectangles. Sketch the curve and the approximating...
Construct and simplify a sum approximating the area above the x-axis and under the curve y = x2 between x = 0 and x = 3 by using n rectangles having equal widths and tops lying above or on the curve. Find the actual area as a suitable limit ОА. 9(n-1)(2n-1) area = 9 square units 2n2 B 9(n + 1) 2n area = 9 square units ос. 3(n-1)(2n-1) n2 area = 6 square units OD 3(n + 1)(2n +...