1.70 m/s ?... 10. Consider the figure on the right. Two boxes move in a frictionless...

Question

Question

1.70 m/s ?... 10. Consider the figure on the right. Two boxes move in a frictionless table. After the collision the two boxes

Answer 1

Answer #1

Let speed of 3 kg block before collision is V m/s

Velocity of 3 kg ball = - V m/s

(Right direction is taken as +ve and left direction as -ve)

By conservation of linear momentum (mass multiplied by velocity)

Momentum before collision = momentum after collision

4×1.70 + 3×(-V)= (4+3)×(-0.4)

6.80 - 3 V = -2.80

3 V = 6.80 + 2.80

3 V = 9.60

V = 3.20 m/s

Answer 2

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