an 1000kg car traveling at 80 m/s takes 19m to stop under full breaking. the same car under similar road conditions, traveling at 160m/s, takes ___________ m to stop under full breaking.
here,
initial speed , u1 = 80 m/s
distance taken to stop , d1 = 19 m
let the accelration be a
using third equation of motion
v1^2 - u1^2 = 2 * d1 * a
0 - 80^2 = 2 * 19 * a
a = - 168.42 m/s^2
when
initial speed , u2 = 160 m/s
let the distance taken to stop be d2
using third equation of motion
v2^2 - u2^2 = 2 * d2 * a
0 - 160^2 = - 2 * d2 * 168.42
d2 = 76 m
the distance taken to stop is 76 m
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