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In the titration of 25.00 ml of 0.10 M HF with 0.10 M NaOHn given ka...

In the titration of 25.00 ml of 0.10 M HF with 0.10 M NaOHn given ka = 3.5 x 10-4 find

initial PH, PH at the equivalence point and Ph at half equivalence point

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Answer #1

Grineni volume of HF - 25.00ml [HF) = 0.10 M kg-3.58164 [NaOH) = 6.10 Initially Finding pH: Hran Mt F- (99) (99) 0 (partial dTotal volume at half equivalent point - 2500L + 12.5 = 37.5 mL = 37.5x10 Liten. Concentration of HF at half equivalent point

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