Question

Task 4 4 Pts A ship with a weight Wo has in seawater a depth of immersion of ho and it displaces a volume of Vo. Before it enters the mouth of a river the weight of the ship is reduced by AW, which results in a decrease of the immersion to depth to h1 and the displaced volume is now V1. When the ship enters the sweet water of the river the depth of immersion is hz and the corresponding displaced volume is V2 (See Fig 1) Calculate: - The volume V (m) - The size of the ships cross section A (m²) - The difference AV = V2-V1 (m) of the displaced Volume in sweet and salty water - The depth of immersion ha in the sweet water (m). Psalty = 1.025 10 kg/m, Psweet = 10 kg/ mg = 10 m/s in mno Fig 1