R code -
#228
qnorm(0.2, lower.tail = FALSE) #For right tail
test
#229
qnorm(0.15) #For left tail test
#230
pnorm(4.8, 4, 0.3, lower.tail = FALSE) #For right
tail test
#231
pnorm(-2.1, -1, 0.6) #For left tail test
Running the above code, we get
228.
Critical value = 0.8416
229.
Critical value = -1.0364
230.
p-value = 0.0038
231.
p-value = 0.0334
Example: An analyst is conducting a test involving the following hypotheses HM 100 vs. H: > 100 The population is known to be normally distributed with a standard deviation of 24. Assume that the sample size is 36. Suppose the acceptance region is X 106.58, a. Find the Type I error b. Calculate the probability of making a Type II error if the population mean actually equals 105.
(c) Under a large sample, given a, a hypothesis test for the mean, Ho : H = Ho vs. He: > Mo, fails to reject the null if & -10 <za Show that this is equivalent to not rejecting H, if Ho is greater than the lower confidence bound of a 100(1 - a)% one-sided confidence interval.
In order to test Ho: Mo = 40 versus H1:# 40, a random sample of size n = 25 is obtained from a normal population with a known o = 6. My x-BAR mean is 42.3 from my sample. Using a TI 83/84 calculator, calculate my P-value with the appropriate Hypothesis Test. Use a critical level a = 0.01 and decide to Accept or Reject Ho with the valid reason for the decision. My P-value greater than a Alpha, so...
and
with minitab please.
4. Consider the hypothesis test Ho: o? =ož vs. H: 0}<03. Suppose that the sample sizes are nl = 5 and n2 = 10, and that S -23.2 and 53-28. Test this hypothesis using 5% significance.
Consider a hypothesis test (Ho: u = 10 vs H,:u > 10) on mean of a normal population with variance known at significance level a = 0.05. Calculate P-value for each of the following test statistics and draw conclusion on whether to reject the null hypothesis. (a) zo = 2.05 (b) zo = -1.84 = 0.4 (c) zo
For the following hypothesis test, where Ho S 10. vs. Hau > 10, we reject Ho at level of significance a and conclude that the true mean is greater than 10, when the true mean is really 8. Based on this information, we can state that we have O made a Type I error. O made a Type Il error. O made a correct decision increased the power of the test.
8. You want to test Ho: p=0.6 vs. Ha: p=0.6 using a test of hypothesis. If you concluded that p is 0.6 when, in fact, the true value of p is not 0.6, then you have made a a. Type I error b. Type I and Type II error c. Type II error d. correct decision
r all the following problems, state Ho and H, compute the test statistic, compute the critical value(s), and state your decision to either reject or fail to r Then restate the decision using simple and nontechnical terms. (3) A simple random sample of 46 measurements of heights of US male adults in centimeters taken eject Ho using either the P-value or critical value method. from a normally distributed population yields sample mean 171.4 and sample standard devi- ation s 11.3....
Practice 9.37 Consider a hypothesis test with Determine whether cach of the following decisions is correct or this bridge ha a. Write th mean n H..μ-180 and H-r<180 Bridge b. For the type II in error. Identify each error as type I or type II a. The true value ofμ is 180 and H. isrepected. b. The true value of a is 179 and H, is rejected c. The true value of μ is 160 and Ho is not rejected....
2. Perform the following .05 level test: Ho: 6 = 2.5 vs. Ha: 0 < 2.5, given a random sample of 10 pieces of data had a mean of 13.6 and a standard deviation of 1.7. Ho: Test Statistic: Ha: p-value: Conclusion (Circle Answer): Fail to Reject Ho R eject Ho