For a process that has Δ?∘= 40 kJ/mol and Δ?∘ = 200 J/Kmol, what is the lowest temperature that the process will be spontaneous?
The lowest temperature at which the process is spontaneous is:
T = ΔH0/ ΔS0 = (40 * 103 J/ mol) / (200 J / K mole) = 200 K
Answer is:
(C) 200 K
For a process that has Δ?∘= 40 kJ/mol and Δ?∘ = 200 J/Kmol, what is the...
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