For geometric distribution, P(X) = p(1-p)x-1
Here, p = 0.7
a) P(X = 1) = 0.7x(1-0.7)0
= 0.7000
b) P(X = 4) = 0.7x(1-0.7)3
= 0.0189
c) P(X = 8) = 0.7x(1-0.7)7
= 0.0002
d) P(X 2) =
P(1) + P(2)
= 0.7 + 0.7x0.31
= 0.9100
e) P(X > 2) = 1 - P(X 2)
= 1 - 0.9100
= 0.0900
Question 1 Your answer is partially correct. Try again. Suppose the random variable Xhas a geometric...
Please answer b
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