In c++, what alternative to malloc line?
Such as
struct Node* newNode(int data)
{
struct Node* node = (struct Node*)
malloc(sizeof(struct Node));
node->data = data;
node->left = NULL;
node->right = NULL;
return node;
}
malloc() function dynamically allocates the memory in C++. But in C++, there is also anoter way to dynamically allocate the memory. We can do this using the new keyword.
So, the code will be
#include<iostream>
using namespace std;
struct Node{
int data;
struct Node *left;
struct Node *right;
};
struct Node* newNode(int data)
{
// dynamically allocate memory
struct Node* node = new( struct Node ); //(struct Node*)malloc(sizeof(struct Node));
node->data = data;
node->left = NULL;
node->right = NULL;
return node;
}
int main()
{
}
In c++, what alternative to malloc line? Such as struct Node* newNode(int data) { struct Node*...
Modify the below code to fit the above requirements:
struct node
{
char data;
struct node *next;
struct node *previous;
} *front, *MyNode, *rear, *MyPointer, *anchor *Valuenode ;
typedef struct node node;
int Push(char input)
{
if(IsFull()==1)
{
printf("The queue is full. Enter the ā^ā character to
stop.\n");
return -1;
}
else if (IsFull()==-1)
{
node *MyNode=(node*)malloc(sizeof(node));
MyNode->data=input;
rear->next=MyNode;
MyNode->previous=rear;
MyPointer=rear=MyNode;
return 1;
}
else
{
node *MyNode=(node*)malloc(sizeof(node));
node *anchor=(node*)malloc(sizeof(node));
MyNode->data=input;
MyPointer=rear=front=MyNode;
MyNode->previous=NULL;
MyNode->next=NULL;
anchor->next=MyNode;
return 0;
}
}
char...
I am stuck on a data structure problem, I am just going off of Geeks for Geeks for help but I need to print 100 random numbers in the range of [1-200]. I can currently only print 5 numbers. Here is my code: #include <stdio.h> #include <stdlib.h> #include <limits.h> using namespace std; //binary tree has data & left and right child struct node{ int data; struct node *left; struct node *right; }; //create a new node struct node* newNode (int...
struct Node * new_11( void ) { // return a new node to be the list anchor struct Node * node = (struct Node *) malloc(sizeof(struct Node)); memset(node, o, sizeof(struct Node)); return node ; struct Node * find_l1(struct Node * anchor, char * word) { // given a pointer to the anchor of the list, and a word, search // the list for the word. return the pointer to the with the word, if found, 7/ or NULL if not...
/* * struct for a single node in a binary tree. data contains
the int
* stored in this node. left and right contain pointers to the
left and
* right subtrees respectively. *
* All of the ints stored in the left subtree is smaller than
data.
* All of the ints stored in the right subtree is larger than
data.
*/
struct node {
int data;
struct node *left;
struct node *right;
};
typedef struct node node;
Write...
This is a code for linked list,
it is about adding a node in the middle of a list, I am really
confused why int i = 2? can't it be 0?
Add to the Middle ā¢ Allocate memory and store data for new node Traverse to node just before the required position of new node Change next pointers to include new node in between struct node *newNode; newNode = malloc(sizeof(struct node)); newNode->data = 4; struct node *temp head; for(int...
#include <stdlib.h> int main() { struct fruit Z; food X = (struct fruit *)malloc(sizeof(struct fruit)); X->taste[4] = (struct flavour *)malloc(sizeof(struct flavour)); X->taste[4]->score = 5; X->link = &Z; return 0; } Given the code above, reverse engineer the necessary data structure and other definitions not shown above. Give your answer as C code.
C PROGRAMMING #include <stdio.h> #include <stdlib.h> struct nodet { int data; struct nodet *link; }; struct nodet *makeAnode(int val) { struct nodet *box; box = malloc(sizeof(struct nodet) ); box->data = val; box->link = NULL; return box; } void printList(struct nodet *L) { struct nodet = *mov; mov = L; while(mov != NULL) { printf("%d ", mov->data); mov = mov->link; } printf("\n"); } // THIS SHOULD COUNT HOW MANY ITEMS (NODES) ARE IN THE LIST. int listLen(struct nodet **L) { int...
Please explain step by step what is going on each step.please clearly explain line by line the working of code . Also provide the output. I would rate positively. Thank you so much . #include <stdio.h> #include <stdlib.h> struct node { int data; struct node *next; }; struct node *head = NULL; void printList() { struct node *ptr = head; printf("\nhead:"); while(ptr != NULL) { printf("node addr:%p \tdata:%d \tnext addr:%p\nā, ptr,ptr->data,ptr->next); ptr = ptr->next; } printf(" [null]\n"); } void insert(int data) { struct node *link = (struct node*) malloc(sizeof(struct node)); link->data = data; link->next = head; head = link; } int main() {...
Consider the following C++ statements: struct node Type int info; node Type *link; nodeType *head, *p, q, *newNode; newNode = new node Type; 1. Write C++ statement to store 50 in the info field of the newNode. 2. Write C++ statement to set the link field of the newNode to NULL. 3. Write C++ statement to make head pointer points to newNode. 4. Write C++ statement to delete the first node in the linked list. (the first an the only...
Hi, I need to make a program in C that reads the type of currency and organizes them into stacks based on currency which can be read back. This is what I have so far, can I get help finishing it? #include <stdio.h> #include <stdlib.h> const float POUND = 1.31; const float YEN = 0.0091; const float RUPEE = 0.014; const float EURO = 1.11; char c; int currValue; float exchangeValue; float finValue; int printValue; struct node { int...