Homework Answers
Mass (M)= 30 g=0.03 kg, Radius(R)= 0.4 cm = 0.004 m. Total mass
is concentrated on the rim so it is like a ring.
a) Moment of intertia(I) = MR^2
I= 0.03*.004^2 = 4.8*10-7 kg.m^2
B) Let torsional constant is K.
so, Time period (T) = 2pi*(I/K)0.5
0.35= 2*3.14*(4.8*10-7/K)0.5
K = 1.547*10-4 Nm/rad
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