008 (part 1 of 3) 10.0 points A clock balance wheel has a period of oscil...

Question

Question

Answer 1

Answer #1

1) Angular velocity of oscillation :

Given: T =0.29 s

w= 2π/T

w = 2×π/ 0.29

w= 21.65(1/s)

2) Moment of inertia(I)

Given : m = 22g=0.022kg , r =0.5cm=0.005

I = mr²

I = (0.022)×(0.005)

I=0.00011kg/m²

3) Torsion constant (K) of the spring

T= [2π(√I)]/K

K= [2π(√I)]/T

K=[ 2π(√(0.00011)]/0.29

K=0.2271Nm

Answer 2

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